Conservation of Mass

The conservation of mass is a fundamental principle of physics and engineering stating that mass can neither be created nor destroyed in an isolated system. In fluid mechanics, it is expressed mathematically as the continuity equation, ensuring that the mass entering a control volume equals the mass leaving it plus any accumulation inside.

1. Principle

For any system of fixed mass: \[ \frac{D m_{\text{system}}}{D t} = 0 \] where \(D/Dt\) is the material (Lagrangian) derivative following the system.

2. Control volume formulation

Using the Reynolds Transport Theorem, the conservation of mass for a control volume (CV) with control surface (CS) is: \[ \frac{d}{dt} \int_{CV} \rho \, dV + \oint_{CS} \rho\, \vec{V} \cdot \vec{n} \, dA = 0 \] where:

The first term is the rate of change of mass inside the CV; the second term is the net mass flux out through the CS.

3. Differential (continuity) equation

Applying the divergence theorem and shrinking the CV to a point yields: \[ \frac{\partial \rho}{\partial t} + \nabla \cdot (\rho \vec{V}) = 0 \]

4. Steady-flow form

For steady flow (\(\partial/\partial t = 0\)), the integral form reduces to: \[ \sum_{\text{inlets}} \dot{m} = \sum_{\text{outlets}} \dot{m} \] where \(\dot{m} = \rho V_n A\) is the mass flow rate through each inlet/outlet, \(V_n\) being the normal velocity component.

5. Worked examples

Example 1: Steady incompressible flow in a pipe junction

Two inlet pipes (1 and 2) merge into one outlet pipe (3). Given: \(\rho = 1000\ \text{kg/m}^3\), \(Q_1 = 0.02\ \text{m}^3/\text{s}\), \(Q_2 = 0.01\ \text{m}^3/\text{s}\). Find \(V_3\) if \(D_3 = 0.1\ \text{m}\).

Solution: \[ Q_3 = Q_1 + Q_2 = 0.03\ \text{m}^3/\text{s} \] Cross-sectional area: \[ A_3 = \frac{\pi D_3^2}{4} \approx 7.854\times 10^{-3}\ \text{m}^2 \] Velocity: \[ V_3 = \frac{Q_3}{A_3} \approx 3.82\ \text{m/s} \]

Example 2: Tank filling

A rigid tank of volume \(V_t = 2\ \text{m}^3\) initially contains air at \(\rho_i = 1.2\ \text{kg/m}^3\). Air enters at \(\dot{m}_{in} = 0.5\ \text{kg/s}\) with no outflow. Find the density after 10 s.

Mass balance: \[ \frac{d}{dt}(\rho V_t) = \dot{m}_{in} \] Integrating: \[ \rho(t) = \rho_i + \frac{\dot{m}_{in}}{V_t} t \] \[ \rho(10) = 1.2 + \frac{0.5}{2} \times 10 = 3.7\ \text{kg/m}^3 \]

6. Applications

7. Notes